Well? You are told that the equation is of the form y= Aexp(4x) and that its graph goes through (2, 2). y= 2= A exp(4(2))= A exp(8). what is A?
Consider the curves in the first quadrant that have equations where is a positive constant.
Different values of give different curves. The curves form a family, .
Let Let be the member of the family that goes through P.
A. Let be the equation of . Find .
Find the slope at of the tangent to .
slope =
C. A curve is perpendicular to at . What is the slope of the tangent to at the point ? slope =
D. Give a formula for the slope at of the member of that goes through . The formula should not involve or .
E. A curve which at each of its points is perpendicular to the member of the family that goes through that point is called an orthogonal trajectory to . Each orthogonal trajectory to satisfies the differential equation
where is the answer to part D.
Find a function such that is the equation of the orthogonal trajectory to that passes through the point .