differential equations

**skabani** · October 28th 2008, 05:12 PM

i need help with some of these, i kind of know how to do it, but i get stuck...

1. dy/dx = (ycosx)/(1+y^2) y(0)=1
i know how to get to the integral of both sides what to i do becuase i get a y^2 on the left?
we are supposed to solve the equation using the values given..

2. dz/dt + e^(t+z)

im not sure how to separate the equations here

3. dp/dt = sqrt(pt) p(1) = 2
im not sure if i got this right but i got p = sqrt (1/4sqrt(t) + 15/4)

please help!! thankss!

**skeeter** · October 28th 2008, 05:37 PM

$\frac{dy}{dx} = \frac{y\cos{x}}{1+y^2}<br />$

$\frac{1+y^2}{y} \, dy = \cos{x} \, dx$

$\int \frac{1}{y} + y \, dy = \int \cos{x} \, dx$

$\frac{dz}{dt} = e^{t+z}$

$\frac{dz}{dt} = e^t \cdot e^z$

$\int e^{-z} \, dz = \int e^t \, dt$

$\frac{dp}{\sqrt{p}} = \sqrt{t} \, dt$

$2p^{\frac{1}{2}} = \frac{2}{3} t^{\frac{3}{2}} + C$

$p^{\frac{1}{2}} = \frac{1}{3} t^{\frac{3}{2}} + C$

$p = \left(\frac{1}{3} t^{\frac{3}{2}} + C\right)^2$

Thread: differential equations

LinkBack

Thread Tools

Display

differential equations

Similar Math Help Forum Discussions

'Differential' in differential equations

Differential Equations-Application of 1st order differential equations 1

Differential Equations:Linear first Order Equations

First Order Differential Equations: Separable Equations and Applications

Differential equations

Search Tags