Let C be the concentration of salt in the tank.
Each minute, 0.04 kg/L * 8L = 0.32 kilos of salt goes in and C kg/L * 8 L = 8C goes out.
Find K with initial condition C(0) = 0.08
After 5 hours, C = 0.4 + almost nothing so Q = C*1000 = 40kg
A tank contains kg of salt and L of water. A solution of a concentration kg of salt per liter enters a tank at the rate L/min. The solution is mixed and drains from the tank at the same rate.
Find the amount of salt in the tank after hours.
I got something like 36 kg and my equation was
A= (320e^(-8t/1000)-320)/-8
but i dont think this is correct