dz/dt + e^(t+z) = 0

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- Oct 26th 2008, 07:48 PMamiv4Differential Equation
dz/dt + e^(t+z) = 0

- Oct 26th 2008, 08:22 PMwhipflip15
Note

$\displaystyle \frac{dz}{dt}=-e^ze^t$

hence

$\displaystyle \int{e^{-z}}dz=-\int{e^t}dt+C$

and continue...