Differential Equation

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October 26th 2008, 07:48 PM
amiv4

Differential Equation

dz/dt + e^(t+z) = 0
October 26th 2008, 08:22 PM
whipflip15

Note
$\frac{dz}{dt}=-e^ze^t$
hence
$\int{e^{-z}}dz=-\int{e^t}dt+C$
and continue...

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