Thread: Differential Equation help!

1. Differential Equation help!

I'm having a real hard time solving this:

$\displaystyle dy/dx -5y = 20cos(5x)$

I have tried mixing everything around and I can't seem to remember how to get y and dy, x and dx on separate sides of the equation. I know I am missing one step!

Any help would be great!
Cheers.

2. Originally Posted by falconed I'm having a real hard time solving this:

$\displaystyle dy/dx -5y = 20cos(5x)$

I have tried mixing everything around and I can't seem to remember how to get y and dy, x and dx on separate sides of the equation. I know I am missing one step!

Any help would be great!
Cheers.
Do you know anything about the integrating factor? This is a scenario where it's applicable. For a little info on the integrating factor, see post #2 of my differential equations tutorial.

--Chris

3. Originally Posted by Chris L T521 Do you know anything about the integrating factor? This is a scenario where it's applicable. For a little info on the integrating factor, see post #2 of my differential equations tutorial.

--Chris
Yeah I do but the example I have in my lecture notes is quite different.

Would I(x) here be e^(5x) or e^(-5x)? Does it matter?

4. Originally Posted by falconed Yeah I do but the example I have in my lecture notes is quite different.

Would I(x) here be e^(5x) or e^(-5x)? Does it matter?
It does matter. The integrating factor would be $\displaystyle \varrho(x)=e^{\int -5\,dx}=e^{-5x}$

--Chris

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