xy' + 3y = sin x/x^2 ive tried using the "general" equation for a linear first order equation but to no avail. any help would be appreciated. im stuck at the bit where i have to integrate sin(x)/x^3 btw
Why? You only need to integrate . First, switch the DE to standard form. Then multiply the whole DE by , which is the integrating factor. You've probably forgotten to multiply in the right-hand side.