# Thread: [SOLVED] 1st Order Diff Equation

1. ## [SOLVED] 1st Order Diff Equation

Hi - I am just checking that I have got the right idea

The following first-order differential equation can be solved by separting the variables

${\frac{dy}{dx}} = x^2 + 2x^2y^2(y>0)$

Am I right in saying that the following is the right separation so I can integrate and solve?

$\int {\frac{dy}{1+2y^2}}= \int x^2 dx$

Thanks in anticipation.

2. Hello,
Originally Posted by Ian1779
Hi - I am just checking that I have got the right idea

The following first-order differential equation can be solved by separting the variables

${\frac{dy}{dx}} = x^2 + 2x^2y^2(y>0)$

Am I right in saying that the following is the right separation so I can integrate and solve?

$\int {\frac{dy}{1+2y^2}}= \int x^2 dx$

Thanks in anticipation.
Yes you are right

3. Yes, that differential equation is separable and your setup is correct.

4. Looks okay to me.

5. Brilliant - thanks for the swift reply. It's really important I get this assignment right so trying to make sure it's all right