[SOLVED] 1st Order Diff Equation

**Ian1779** · September 22nd 2008, 01:20 PM

Hi - I am just checking that I have got the right idea

The following first-order differential equation can be solved by separting the variables

${\frac{dy}{dx}} = x^2 + 2x^2y^2(y>0)$

Am I right in saying that the following is the right separation so I can integrate and solve?

$\int {\frac{dy}{1+2y^2}}= \int x^2 dx$

Thanks in anticipation.

**Moo** · September 22nd 2008, 01:21 PM

Hello,

Originally Posted by Ian1779

Hi - I am just checking that I have got the right idea

The following first-order differential equation can be solved by separting the variables

${\frac{dy}{dx}} = x^2 + 2x^2y^2(y>0)$

Am I right in saying that the following is the right separation so I can integrate and solve?

$\int {\frac{dy}{1+2y^2}}= \int x^2 dx$

Thanks in anticipation.

Yes you are right

**icemanfan** · September 22nd 2008, 01:21 PM

Yes, that differential equation is separable and your setup is correct.

**Matt Westwood** · September 22nd 2008, 01:22 PM

Looks okay to me.

**Ian1779** · September 22nd 2008, 01:24 PM

Brilliant - thanks for the swift reply. It's really important I get this assignment right so trying to make sure it's all right

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