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Math Help - [SOLVED] 1st Order Diff Equation

  1. #1
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    [SOLVED] 1st Order Diff Equation

    Hi - I am just checking that I have got the right idea

    The following first-order differential equation can be solved by separting the variables

    {\frac{dy}{dx}} = x^2 + 2x^2y^2(y>0)

    Am I right in saying that the following is the right separation so I can integrate and solve?

    \int {\frac{dy}{1+2y^2}}= \int x^2 dx

    Thanks in anticipation.
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  2. #2
    Moo
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    Hello,
    Quote Originally Posted by Ian1779 View Post
    Hi - I am just checking that I have got the right idea

    The following first-order differential equation can be solved by separting the variables

    {\frac{dy}{dx}} = x^2 + 2x^2y^2(y>0)

    Am I right in saying that the following is the right separation so I can integrate and solve?

    \int {\frac{dy}{1+2y^2}}= \int x^2 dx

    Thanks in anticipation.
    Yes you are right
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  3. #3
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    Yes, that differential equation is separable and your setup is correct.
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  4. #4
    Super Member Matt Westwood's Avatar
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    Looks okay to me.
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  5. #5
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    Brilliant - thanks for the swift reply. It's really important I get this assignment right so trying to make sure it's all right
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