# Solve the differential equation

• September 13th 2008, 03:15 AM
gingerbailey
Solve the differential equation
A calf that weighs w_o pounds at birth gains weight at the rate shown below where w is weight in pounds and t is time in years. (w_o is w sub o)

dw/dt = 1200 - w
• September 13th 2008, 05:08 AM
mr fantastic
Quote:

Originally Posted by gingerbailey
A calf that weighs w_o pounds at birth gains weight at the rate shown below where w is weight in pounds and t is time in years. (w_o is w sub o)

dw/dt = 1200 - w

$\Rightarrow \frac{dt}{dw} = \frac{1}{1200 - w}$, subject to the boundary condition that at t = 0, $w = w_0$.

Integrate with respect to w, use the boundary condition to get the arbitrary constant and, I suppose, make w the subject.