Solve the following differential equation using the substitution given: , by substituting y = zx. I got to a stage where zx = 2 (not sure if I am right)...and then I don't know how to continue. Please help! Thank you!
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Hello, Originally Posted by Tangera Solve the following differential equation using the substitution given: , by substituting y = zx. I got to a stage where zx = 2 (not sure if I am right)...and then I don't know how to continue. Please help! Thank you! Don't forget that z is a function of x. You must arrive to
Originally Posted by Moo Hello, Don't forget that z is a function of x. You must arrive to Yes I reached there and got xz = 2 after intergrating. And then I am stuck. X.x
Originally Posted by Tangera Yes I reached there and got xz = 2 after intergrating. And then I am stuck. X.x Oops sorry ^^ Then, you know that y=xz... and you substitute
Originally Posted by Moo Oops sorry ^^ Then, you know that y=xz... and you substitute Hmm...just to check...do I substitute y = xz = 2 into the given differential equation? But if so, then I get = 0...and I am lost! >.<
Originally Posted by Tangera Hmm...just to check...do I substitute y = xz = 2 into the given differential equation? But if so, then I get = 0...and I am lost! >.< Yes, and too
Originally Posted by Moo Yes, and too The answer I was given is 2x/(x+c)....but I don't know how to get there...Thanks for the help!
Haha I know why Yes I reached there and got xz = 2 after intergrating. And then I am stuck. X.x The exact solution shall be (c is the constant of integration !) Since
Ahhh I see!! Thank you very much, Moo!
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