Use reduction of order to find the second solution of the differential equation. Note: Y1 is the first solution.
x y'' + y' = 0; Y1= lnx
I know the answer is Y2= 1 but i wonder how they got this, could someone explain me....Please!!!
Thank you
Use reduction of order to find the second solution of the differential equation. Note: Y1 is the first solution.
x y'' + y' = 0; Y1= lnx
I know the answer is Y2= 1 but i wonder how they got this, could someone explain me....Please!!!
Thank you
The solution proceeds the same way as in this thread.
$\displaystyle y_2(x) = v(x) \cdot y_1(x)$
Sub this into your differential equation and you will get an equation in the form
$\displaystyle a(x)v'' + b(x)v' = 0$
which you can do a reduction of order on.
If you are still having troubles after this hint, perhaps you should show us your work so we can better see where you need help.
-Dan