$\displaystyle y’’’ + 6y’’ + 12y’+ 8y = 12e^{-2x}$

EDIT: Hey, why don't the primes show up? Here's it without using the code

y’’’ + 6y’’ + 12y’+ 8y = 12e^(-2x)

trying using both method of undetermined coefficient & variation of parameters.

Y’’’ + 6y’’ + 12y’+ 8y = 12e^(-2x)? - Yahoo! Answers