# Differential question

• June 13th 2008, 02:40 PM
wren17
Differential question
Why can both y = x - 3 and y = x + 2 both be considered solutions to the differential equation dy/dx - 1 = 0?
• June 13th 2008, 02:46 PM
wingless
Because,

$\frac{dy}{dx}=1$

$dy = dx$

$y = x + C$

So any solution in the form $y=x+C$ is correct.