I am a bit confused on variation of parameters for solving differential equations. I understand the methods of coefficients but variation of parameters is a bit confusing. I would i use it to solve this:
y'' - 5y' = -2x + 2
Like how would i find independent solutions u1(x), u2(x) which would help me find derivatives v1¢(x) and v2¢(x) which then i get a general solution. I am confused on the steps and how to solve.
Thanks
Phil
You can check this out. I outlined a VP problem in post #6.
http://www.mathhelpforum.com/math-he...eous-help.html
That is what i did and doesnt seem to be right. I integrated W1/W and W2/W
For v1' and v2' above is it:
v1' = ((2x-2)e^(5x))/(5e^(5x)) integrated
which gives
v1 = ((1/5)*(x-2)*x)
v2' = (-2x+2)/(5e^(5x)) integrated
gives
v2 = ((2/125)*e^(-5*x) * (5*x-4))
What am I doing wrong?
hmmmm yea Im also using maple.
The questions am trying to answer this:
Now assume that the solution of the original d.e. is of form
y(x) = u1v1 + u2+v2
where u1, u2 are the functions you entered in the first part. Determine the derivatives v1'(x) and v2'(x).