y2+(7/m)y+(5/m)=0 (auxiliary eqn) where m=2.45=49/2
k so used quadratic formula get one realroot 20/14
so (complementary eqn) x=Ae^1.43t displacement time btw
prior to a.e have x''+(7/m)x'+(5/m)x=g g=10ms^-2
therefore to consider g do trial x = y
5y/m 10
y = 4.9
therefore x = Ae^1.43t + 4.9
FROM HERE IM STUCK
answer is x = 4.9 - (7.01t + 4.9)e^-1.43t
if n e onecan ee if ive gone wrong ,,,or show me wht t do now that'd be gr8 cheers!!!