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Thread: integrate dv / srt rt ( 1 +v^2)

  1. #1
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    integrate dv / srt rt ( 1 +v^2)

    is it wrong to integrate dv / srt rt ( 1 +v^2) = ( (1+v^2)^0.5) / (2v)(0.5) ? integrate dv / srt rt ( 1 +v^2)-img_20160301_153109-1-.jpg
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  2. #2
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    Re: integrate dv / srt rt ( 1 +v^2)

    $\displaystyle \int \dfrac{dv}{\sqrt{1+v^2}}$

    $v=\tan{t}$

    $dv=\sec^2{t} \, dt$

    $\displaystyle \int \dfrac{\sec^2{t}}{\sqrt{1+\tan^2{t}}} \, dt = \int \sec{t} \, dt = \ln|\sec{t}+\tan{t}|+C$

    $\ln|\sqrt{1+v^2}+v|+C$


    So, yes ... I'd say it's wrong.

    btw ... when are you going to learn latex and start posting something legible for a change?
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