just take the Laplace transform of $H(t-2)$

You should know that

$\mathscr{L} \{H(t) \} = \dfrac 1 s$ and that

$\mathscr{L} \{ f(t-t_0) \} = e^{-s t_0} F(s)$

given these the transform of $H(t-2)$ should be pretty trivial to compute.

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- Apr 27th 2014, 09:26 AM #1

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## Help on Heaviside

Hi, I am pretty lost on trying to solve this problem.

y'' + y' = H(t-2), y(0)=1, y'(0)=0

I know the first part is to do the Laplace on the left side of the equation

s^{2}Y-s+sY-1

Y(s2+s)-s-1 = H(t-2)

I don't know what to do after. Can someone please help explain what to do....

The answer choices are

A)

B)

C)

D)

Thanks

- Apr 27th 2014, 09:42 AM #2

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## Re: Help on Heaviside

just take the Laplace transform of $H(t-2)$

You should know that

$\mathscr{L} \{H(t) \} = \dfrac 1 s$ and that

$\mathscr{L} \{ f(t-t_0) \} = e^{-s t_0} F(s)$

given these the transform of $H(t-2)$ should be pretty trivial to compute.