Re: differential equations,

You are producing A at rate k and it is decaying at a rate , so . Your equation is incorrect since some of the A produced has decayed for a long time and some for a short time.

To solve this equation, substitute . Everything else is pretty straightforward. Let us know if you have any trouble.

- Hollywood

Re: differential equations,

Thanks,

This is my solution:

I got the general solution using the integrating factor method

for part v)

C is some constant greater than k/a

for vi I subbed in the given B(t) into the differential equation I wrote for dB/dt

and (not sure about this)

then for B(t) I get