# Thread: Differential Equations Help pls

1. ## Differential Equations Help pls

1.Using separation of variable , solve the differential Equation

dy/dx = ((3x^2+4x+2)/(2(y-1)))

y(0) = -1

Thank you

2. ## Re: Differential Equations Help pls

$\dfrac{dy}{dx}=\dfrac{3x^2+4x+2}{2(y-1)}$

$2(y-1)dy=(3x^2+4x+2)dx$

you should be able to finish it from here.

3. ## Re: Differential Equations Help pls

So y^2 -2y = x^3+2x^2+2x+C

what should i do with y^2-2y(2 y variable) that is the question ?

I'm newbie with dif equ i don't have any experience with problem
i just learn a easy seperation problem
ex dy/dx = y that y has only one variable on the left side

4. ## Re: Differential Equations Help pls

Your implicit solution is fine, but if you really want to get y explicitly in terms of x, complete the square.

5. ## Re: Differential Equations Help pls

Complete the square is the basic but I'm still don't know
How to complete the square in this case

Anybody solution pls??

6. ## Re: Differential Equations Help pls

Come on...

\displaystyle \begin{align*} y^2 - 2y &= y^2 - 2y + \left( -\frac{2}{2} \right)^2 - \left( -\frac{2}{2} \right) ^2 \\ &= y^2 - 2y + (-1)^2 - (-1)^2 \end{align*}

Finish it.