which is it?

4t or 4y?

Results 1 to 5 of 5

- February 14th 2014, 09:30 PM #1

- Joined
- Mar 2011
- Posts
- 22

## cos^2(t)y'+4y=5

I'm kind of stuck on this problem. The problem given is cos

^{2}(t)y' + 4y = 5 , where y(0) = 6

So what I got are no where near the choices give.

When I Plug in y(0)=6, I get C = 6....

The choices for the answers are

y(t) = 4+2e^{tan(t)}

y(t) = 4+2e^{-tan(t)}

- February 14th 2014, 09:53 PM #2

- Joined
- Nov 2013
- From
- California
- Posts
- 3,420
- Thanks
- 1392

- February 14th 2014, 10:03 PM #3

- Joined
- Nov 2013
- From
- California
- Posts
- 3,420
- Thanks
- 1392

- February 15th 2014, 12:31 AM #4

- Joined
- Jun 2009
- Posts
- 671
- Thanks
- 136

- February 15th 2014, 02:09 PM #5

- Joined
- Nov 2013
- From
- California
- Posts
- 3,420
- Thanks
- 1392