which is it?

4t or 4y?

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- Feb 14th 2014, 10:30 PM #1

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## cos^2(t)y'+4y=5

I'm kind of stuck on this problem. The problem given is cos

^{2}(t)y' + 4y = 5 , where y(0) = 6

So what I got are no where near the choices give.

When I Plug in y(0)=6, I get C = 6....

The choices for the answers are

y(t) = 4+2e^{tan(t)}

y(t) = 4+2e^{-tan(t)}

- Feb 14th 2014, 10:53 PM #2

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- Feb 14th 2014, 11:03 PM #3

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- Feb 15th 2014, 01:31 AM #4

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- Feb 15th 2014, 03:09 PM #5

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