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Math Help - Differential Equation with Initial Value

  1. #1
    Junior Member ReneG's Avatar
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    Differential Equation with Initial Value

    Solve the differential equation \mathrm{d}y = y^2(1 + x^2) with the initial value y(0)=1

    I can't solve this because I'm used to the idea that differentials must come in pairs, is there a typo in the problem or is it something I just don't know?
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  2. #2
    Junior Member FelixFelicis28's Avatar
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    Re: Differential Equation with Initial Value

    Quote Originally Posted by ReneG View Post
    Solve the differential equation \mathrm{d}y = y^2(1 + x^2) with the initial value y(0)=1

    I can't solve this because I'm used to the idea that differentials must come in pairs, is there a typo in the problem or is it something I just don't know?
    I think this should be y' = y^2 (1+x^2), \ y(0) = 1 OP.

    With regards to the actual question, this is a fairly simple DE to solve - do you know what a separable DE is?
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