Attachment 29066 Could someone work out how the third equation (43) becomes the fourth equation (44). Seems like magic to me. Where does the K on the Tsub0 term go?

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- Aug 26th 2013, 06:24 PMiamloganmanIntegrating Factors method
Attachment 29066 Could someone work out how the third equation (43) becomes the fourth equation (44). Seems like magic to me. Where does the K on the Tsub0 term go?

- Aug 26th 2013, 06:41 PMtwizterRe: Integrating Factors method
Just integrate the 3rd equation carefully, you will see (Wink)

- Aug 26th 2013, 07:03 PMiamloganmanRe: Integrating Factors method
it's pretty clear that is what I am having trouble with

- Aug 26th 2013, 07:23 PMtwizterRe: Integrating Factors method
lol. When you integrate the 1st term on the RHS, integral of $\displaystyle e^{kt}$ is $\displaystyle e^{kt}/k$ which cancels out the k in the numerator. The integral of the LHS is $\displaystyle ue^{kt}$ itself. The constant c is a constant of integration. First just integrate on both sides and divide both sides by$\displaystyle e^{kt}$. You will arrive at the answer. Hope this helps.