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Math Help - solve differential equations

  1. #1
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    solve differential equations

    for the first one, "However when k=0, y=1. This also satisfies (1)" what to they mean by that? there is no 'k' in (1) is dy/dx = 0 because k=0? why?

    for the second one, 'however when y=1,-1, dy/dx=0' how to get dy/dx=0?
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  2. #2
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    Re: solve differential equations

    Hey muddywaters.

    Hint: When y = c (i.e. a constant) then what is the derivative?
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  3. #3
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    Re: solve differential equations

    Quote Originally Posted by chiro View Post
    Hey muddywaters.

    Hint: When y = c (i.e. a constant) then what is the derivative?
    oh thanks. for the second one i got stuck because i thought should substitute y=1,-1 into x=-\sqrt{1-y^2}+C that would give me x = c which cannot give dy/dx = 0. but actually y=1,-1 is itself the solution.
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