for the first one, "However when k=0, y=1. This also satisfies (1)" what to they mean by that? there is no 'k' in (1) is dy/dx = 0 because k=0? why?

for the second one, 'however when y=1,-1, dy/dx=0' how to get dy/dx=0?

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- July 20th 2013, 09:47 AMmuddywaterssolve differential equations
for the first one, "However when k=0, y=1. This also satisfies (1)" what to they mean by that? there is no 'k' in (1) is dy/dx = 0 because k=0? why?

for the second one, 'however when y=1,-1, dy/dx=0' how to get dy/dx=0? - July 20th 2013, 07:07 PMchiroRe: solve differential equations
Hey muddywaters.

Hint: When y = c (i.e. a constant) then what is the derivative? - July 21st 2013, 12:08 AMmuddywatersRe: solve differential equations