I have the following question to work out:-

A defibrillator consists of a open circuit containing a capacitor of 40 $\displaystyle \mu$F and an inductor of 0.05H. A patient has a resistance of 60$\displaystyle \Omega$ when the defibrillator is discharged through him. Find the current during discharge if the capacitor is charged initially to 5000V.

Solving the second order linear D.E. for RLC circuits from:

$\displaystyle L\frac{d^2Q}{dt^2} + R\frac{dQ}{dt} + \frac{1}{C}Q = E$

I got the following general solution for Q (where L = 0.05, R = 60, C = $\displaystyle 40 x 10^{-6}$ and E = 5000) -

$\displaystyle Q(t) = c_{1} e^{-600t} cos 100 \sqrt{14}t + c_{2} e^{-600t} sin 100 \sqrt{14}t + 0.02$

I am confused as how to get $\displaystyle c_{1}$ and $\displaystyle c_{2}$. I used the intial conditions of t=0 and Q=0 to get $\displaystyle c_{1}$ = -0.02 but I am unsure as how to get $\displaystyle c_{2}$.

Also how do I get the current? Would it be also at t=0?

Any suggesstions would be greatly appreciated.