Hi, I really need help on this ODE question.
Attachment 27362
Thanks,
Sofina
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Hi, I really need help on this ODE question.
Attachment 27362
Thanks,
Sofina
Hey sofv66.
Show us what you have tried.
So, dy/dx=3y^2/3
int y^-2/3 = int 3
3y^1/3 = 3x +c
y=(x+c)^3
is all I have done.
Can you help me to finish the question please.
Thank you.
I'm guessing that this function is defined only for an initial value onwards.
If this is the case, you need to substitute in your initial value into your function to obtain a value of c and show that the function has the right form.
So your initial value is at x = a with f(a) = b.
You can say that for this problem, you only define function from the initial value onwards to justify the zero before x = a.
Attachment 27445
can you solve this and you will get the result of
arctan(α/s)