How do I solve an equation that is missing the independent variable?
$\displaystyle 2y^2* y'' + 2y(y')^2 = 1$
I have an idea but i'm not sure if it will work
If y = $\displaystyle ax^2 + bx + c $ then
$\displaystyle 2y^2*y''$ = 4th degree polynomial
$\displaystyle 2y*(y')^2 =$ 4th degree polynomial
so you would have to solve for the coefficients so that they cancel out.