How do I solve an equation that is missing the independent variable?

$\displaystyle 2y^2* y'' + 2y(y')^2 = 1$

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- Feb 25th 2013, 06:48 PMcolerelm1Solving the second order equation?
How do I solve an equation that is missing the independent variable?

$\displaystyle 2y^2* y'' + 2y(y')^2 = 1$ - Feb 25th 2013, 07:58 PMjakncokeRe: Solving the second order equation?
I have an idea but i'm not sure if it will work

If y = $\displaystyle ax^2 + bx + c $ then

$\displaystyle 2y^2*y''$ = 4th degree polynomial

$\displaystyle 2y*(y')^2 =$ 4th degree polynomial

so you would have to solve for the coefficients so that they cancel out. - Feb 26th 2013, 12:10 AMJJacquelinRe: Solving the second order equation?
- Feb 26th 2013, 03:25 AMHallsofIvyRe: Solving the second order equation?
I should have read JJacqueline's post first- she did exactly the same thing.

- Feb 26th 2013, 04:29 AMJJacquelinRe: Solving the second order equation?