v=ln(xy)
after cleaning up,
dv/v+1 = dx/x
Integrating that^
ln(v+1) = ln x + C
v+1 = Cx
ln(xy) +1 = Cx
Sorry if it is disorganized, but im new to the forums and format.
Im not sure if i solved it right.
Thanks.
v=ln(xy)
after cleaning up,
dv/v+1 = dx/x
Integrating that^
ln(v+1) = ln x + C
v+1 = Cx
ln(xy) +1 = Cx
Sorry if it is disorganized, but im new to the forums and format.
Im not sure if i solved it right.
Thanks.