Schwarz Reflection Principle for (Real) Harmonic Functions
Assume
is harmonic in
and
, where
is the open ball
of radius
about the origin in
,
being the upper half-ball: 
(This is problem #2.5.-something in Evans PDE text).
We want to show (under the assumed regularity of
) that the odd extension of
into
provides us a with a harmonic function on all of
. That is, if
in
,
on
, and
in
, then
is harmonic and
in all of
.
Okay, it is obvious
is
in the separated sets
and
. Since
is
upto the boundary of
(in particular upto
), then it is also clear that
is
in all of
. We also see that
satisfies the mean-value-properties in
and
, and also on
because of the odd symmetry.
Here's my problem, and of all the proofs I have seen, this is overlooked. The mean-value properties of
are satisfied on
,
and
, yes. But only when viewed individually. How do you use the fact that
to then show that the mean-value property is satisfied in all of
(not just the three aforementioned sets when the spherical averages are restricted to the individuals sets). In other words, how do you justify the extending of a spherical average across the three sets (say at a point
with radius sufficiently large to intersect all three sets, but sufficiently small to remain in
).
I will reiterate this: every proof I have seen does not make explicit reference to the
regularity of
. If the mean-value property can be demonstrated without
regularity, then all one needs is
regularity (not even differentiability) of
in order to conclude
is harmonic (it is easy to prove that a continuous function which satisfies the mean-value property at every point in an open set is harmonic there). But if this were the case, then why would Evans (and other texts where the problem is posed) be insistent on requiring
being
in
, and thus
in
?
NOTE: In part (b) of this problem, Evans drops the hypothesis that
is
upto the boundary, only that
. But the suggested proof is entirely different: apply the Poisson integral formula for harmonic functions on a disc. Indeed, one solves the problem

where
on the upper boundary and
on the lower boundary. The solution is given by the Poisson integral formula, and computing
where
, we find
. From uniqueness, we conclude that
as above (the odd extension of
), and the theorem is proved.
Anyway, if anyone could help me fill in the details of the mean-value property argument in the first part, I would appreciate it!