Did you remember to take the square root after substituting 2 and 3?
I need some help or guidance reviewing the fundamental theorem of calculus. I'm supposed to evaluate the integral (d/dt sqrt(2+2t^4)) dt from 2 to 3. I don't know if I'm reading the problem right, but I took the derivative(d/dt) of sq rt (2+2t^4) and got (4t^3)/(sqrt(2+2t^4). I then integrated that and got the original expression. I then plugged in 3 and 2 for the t values and ended up with something like 130. I do not think this is correct. Any help or guidance would be appreciated.