Hi All,

Could not solve this one:12-x-3y+(x-y+4)y'=0 , y(0)=1

I tried to find an integrating factor in order to make it an exact equation but did not succeed.

would appreciate your help!

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- Jan 11th 2013, 06:24 AMAmitromemIntegrating factos - first order DE
Hi All,

Could not solve this one:__12-x-3y+(x-y+4)y'=0 , y(0)=1__

I tried to find an integrating factor in order to make it an exact equation but did not succeed.

would appreciate your help! - Jan 11th 2013, 07:02 AMCbarker1Re: Integrating factos - first order DE
Put the differential equation into standard form. then Begin to find the integrating factor.

- Jan 11th 2013, 01:23 PMAmitromemRe: Integrating factos - first order DE
If I understand correctly the standard form has to be: y' + P(x)*y=Q(x) and specifically: y'-3y/(x-y+4)=(x-12)/(x-y+4)

but since there is a polynomial in the denominator of P(x) which includes y this is not the standard form.

Right? - Jan 12th 2013, 05:21 PMProve ItRe: Integrating factos - first order DE
I believe the standard form Cbarker was referring to is actually $\displaystyle \displaystyle \begin{align*} f(x,y)\,dx + g(x,y)\,dy = C \end{align*}$, which you can then find an integrating factor for to make the equation an exact equation.