method of characteristic !!!
(Rofl) Hi everyone,
i have a problem for solving a partial differential equation with the method of characteristic. I already spent lot of time and I have not yet found the solution
http://latex.codecogs.com/gif.latex?...+y^2, x>0, y>0
In fact, when I try to solve du/dt after I already obtained before dx/dt and dy/dt, I have an expression an expression which depends on t and u. Impossible to solve...
If someone can help me pleasseeeee!!!!
Re: method of characteristic
I advanced in my problem but I'm again in trouble
I transformed my expression with polar coordinates
so (c is my constant)
Now I have to find the value of my constant by caracteristics method
so I continue my reasoning:
we find before that
moreover with my initial condition
so i guess
in short I feel that's wrong
someone can help me please??