I have got y'+y = sin x. How do I start this question? Help please!. THank you.
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Originally Posted by tjsdndnjs I have got y'+y = sin x. How do I start this question? Help please!. THank you. The solution will be of the form . To get (the homogeneous solution) set . To get the particular solution I'd use the method of undetermined coefficients. -Dan
Originally Posted by topsquark The solution will be of the form . To get (the homogeneous solution) set . To get the particular solution I'd use the method of undetermined coefficients. -Dan Really? It's not a second order linear DE, it's first order linear... The integrating factor is , so we have Now to solve that ugly integral, use integration by parts... So the solution to your DE is
Originally Posted by Prove It Really? It's not a second order linear DE, it's first order linear... (shrugs) It's my favorite method. I've always found the integrating factor method to be somewhat clumsy. But that's my own opinion. -Dan
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