# partial differential equation

• Nov 10th 2012, 10:02 AM
MAX09
partial differential equation
Let u = u(x,y) be the complete integral of the PDE

$\frac {\partial u} {\partial x} . \frac {\partial u} {\partial y} = xy$ passing through the points
(0,0,1) and (0,1,1/2) in the x-y-u space.

Compute the value of u(x,y) evaluated at (-1,1) is _____

I'm completely lost with respect to this problem.. 'd be great if someone can show me the right direction.

Thanks,
• Nov 11th 2012, 02:40 AM
tom@ballooncalculus
Re: partial differential equation
\displaystyle \begin{align*} \\ \frac {\partial u} {\partial x} . \frac {\partial u} {\partial y}\ &=\ xy &=\ (kx) (\frac{y}{k})\ & \Leftarrow\ \LARGE{[}\ \frac {\partial u} {\partial x} = kx \And \frac {\partial u} {\partial y} = \frac{y}{k}\ \Huge{]} \end{align*}

Spoiler:

Just in case a picture helps...

http://www.ballooncalculus.org/draw/pde/one.png

Spoiler:

\displaystyle \begin{align*} \text{E.g.,}\ \ u(0,0)\ =\ 1\ =\ \frac{k}{2}(0)^2 + \frac{1}{2k}(0)^2 + c\ \Rightarrow\ c = 1 \\ \\ \text{And, e.g.,}\ \ u(0,1)\ =\ \frac{1}{2}\ =\ \frac{k}{2}(0)^2 + \frac{1}{2k}(1)^2 + 1\ \Rightarrow\ \text{etc.} \end{align*}

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• Nov 11th 2012, 03:36 AM
MAX09
Re: partial differential equation
Tom, thanks for the reply! that definitely showed a lot of light on how to get started !!! Thanks again, TOM@ballooncalculus... The image was thoughtfully designed... :)