Hello all ,
i have the equation
now i managed to find the formula for it and got to:Code:(1+x^2)y'+y=arctgx
where ~ is the sign for integralCode:y=e^-arctanx[~(arctanx*e^tanx*dx)/(1+x^2)]
now i'm supposed to do t=arctanX
but don't understand where i get the dt from ?
how do i find the DT is what i'm asking here
thanks to all the helpers !!