Solve [(alpha)^2]u''+a*e^u=0 by multiplying it by du/dx and integrating it in x I just keep going in circles and ending up with the original problem.
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Originally Posted by cheesecake91 Solve [(alpha)^2]u''+a*e^u=0 by multiplying it by du/dx and integrating it in x I just keep going in circles and ending up with the original problem. Now, if we let , then and the DE becomes Finish it.
Thanks! I was thinking it had something to do with substitution but couldn't figure it out.
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