Solve [(alpha)^2]u''+a*e^u=0 by multiplying it by du/dx and integrating it in x

I just keep going in circles and ending up with the original problem.

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- Nov 2nd 2012, 05:49 PMcheesecake91Second Order Differential Equation
Solve [(alpha)^2]u''+a*e^u=0 by multiplying it by du/dx and integrating it in x

I just keep going in circles and ending up with the original problem. - Nov 2nd 2012, 08:00 PMProve ItRe: Second Order Differential Equation
- Nov 3rd 2012, 11:13 AMcheesecake91Re: Second Order Differential Equation
Thanks! I was thinking it had something to do with substitution but couldn't figure it out.