Please help me find general solution of y' + y^2 = 1 and y(0)=2 y' = 1(y^-2) I try to use Bernoulli's but it did not work because there is no y term y' + p(x)y = q(x)y^n v' + (1-n)p(x)v = (1-n)q(x)
Follow Math Help Forum on Facebook and Google+
use separation of variables: dy/1-y^2=dx
View Tag Cloud