How would I go about solving this form of differential equation?

(dx/dt) = (12b)(18bt-x)

So it becomes

(dx/dt) = (125(b^2)t)-(12bx)

Use the integrating factor method?

(dx/dt) + (12bx) = (125(b^2)t)

Or not - I am totally stumped with this...

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- Oct 30th 2012, 01:56 PMMaverickUK82Which method for solving this form of differential equation?
How would I go about solving this form of differential equation?

(dx/dt) = (12b)(18bt-x)

So it becomes

(dx/dt) = (125(b^2)t)-(12bx)

Use the integrating factor method?

(dx/dt) + (12bx) = (125(b^2)t)

Or not - I am totally stumped with this... - Oct 30th 2012, 02:23 PMMarkFLRe: Which method for solving this form of differential equation?
Your product of 12 and 18 is not 125 (it is 216), but otherwise, yes, this is a linear equation, and you want to calculate an integrating factor.