1. y2(dx/dy) + xy -4y2 =1
I try to simplify to
(dx/dy) + x/y -4 = 1/y2
(dy/dx) = y2 - x/y + 1/4
I don't know how to go next (I try to use integrating factor but it's not working)
2. dy/dx = y(y+3)
(dy/dx)/y(y+3) = 1
Integral (dy/dx)/y(y+3) = Integral 1 dx
then I get
1/3 In(y) - 1/3 In(y+3) = x + c
(I'm not sure about this) My calculus is rusty. I don't remember how to get this number I just remember the formula
Someone please explain or correct.
Then I'm not sure how to get
y = .......