1. y

^{2}(dx/dy) + xy -4y

^{2 }=1

I try to simplify to

(dx/dy) + x/y -4 = 1/y

^{2 }(dy/dx)

^{ = }y

^{2} - x/y + 1/4

I don't know how to go next (I try to use integrating factor but it's not working)

2. dy/dx = y(y+3)

(dy/dx)/y(y+3) = 1

Integral (dy/dx)/y(y+3) = Integral 1 dx

then I get

1/3 In(y) - 1/3 In(y+3) = x + c

(I'm not sure about this) My calculus is rusty. I don't remember how to get this number I just remember the formula

Someone please explain or correct.

Then I'm not sure how to get

y = .......