Originally Posted by

**nivek0078** I'm getting a incorrect answer for Given 2xy(dy/dx) + y^2 - 1 = 0 find solution A) (1,0) B) (0,1) in x-y plane. Please tell me where i'm screw up and how to fix it.

This is my workout:

2xy(dy/dx) + y^2 - 1

-seperate:

y^2 +2y dy=-2x + 1 dx

-intergrate:

(y^3/3)+(y^2) = x-(x^2) +C

This is where my problem is, I'm not sure from here how to do the following.

-divide through by y

y=square root (-x+C/y+3) I don't think that is right and if it is what is my next step in getting rid of y on the right side?