Your integrating factor would be:
Multiplying the ODE by this factor will give you the product of differentiation on the left:
Now, use integration by parts on the right...
Code:y'-y=7te2t , y(0)=1
I would like to know how to solve this Differential Equation. I think I have to find the integrating factor.
It does look like it follows the the standard formSo the integrating factor is e∫pxCode:y'+px=qx
Would the integrating factor be e∫-y ?