Finding a solution given initial value problem

Printable View

Sep 22nd 2012, 07:55 AM
terrygrada

Finding a solution given initial value problem

Code:

y'-y=7te^{2t ,} y(0)=1

I would like to know how to solve this Differential Equation. I think I have to find the integrating factor.

It does look like it follows the the standard form

Code:

y'+px=qx

So the integrating factor is e^∫pxWould the integrating factor be e^∫-y ?

Thanks
Sep 22nd 2012, 08:16 AM
MarkFL

Re: Finding a solution given initial value problem

Your integrating factor would be:

$\mu(t)=e^{\int(-1)\,dt}=e^{-t}$

Multiplying the ODE by this factor will give you the product of differentiation on the left:

$e^{-t}\frac{dy}{dt}-e^{-t}y=7te^t$

$\frac{d}{dt}\left(e^{-t}y \right)=7te^t$

$\int\,d\left(e^{-t}y \right)=7\int te^t\,dt$

Now, use integration by parts on the right...
Sep 22nd 2012, 12:41 PM
terrygrada

Re: Finding a solution given initial value problem

How do you insert mathematical functions on these forums the way you inserted the integral sign?

And thanks for the integrating factor.
Sep 22nd 2012, 01:04 PM
MarkFL

Re: Finding a solution given initial value problem

Use the TEX tags, for example enclosing the code \int_a^b f(x)\,dx=F(b)-F(a) within the tags produces:

$\int_a^b f(x)\,dx=F(b)-F(a)$

All times are GMT -8. The time now is 11:59 AM.

Copyright © 2005-2017 Math Help Forum. All rights reserved.