$\displaystyle dy/dx=x^{-1}(2y^{\frac{1}{2}}-2y) $

have reduce to $\displaystyle \int\frac{1}{2y^{\frac{1}{2}}-2y}dy=\int\frac{1}{x}dx $

i have tried the u substitution but still unable to reduce the left-hand side to its simplest form, pls what is it am missing here?

thanks!