an equation of this form: $\displaystyle f(D)y=\exp^{ax}cosax $

pls how do one approach it? thanks.

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- Sep 13th 2012, 06:01 AMlawochekeldifferential operator!
an equation of this form: $\displaystyle f(D)y=\exp^{ax}cosax $

pls how do one approach it? thanks. - Sep 13th 2012, 07:33 AMtopsquarkRe: differential operator!