$\displaystyle [x^2\exp^\frac{y}{x}-y^2]dx + xydy = 0 $
pls refer to the above equation, i need help on how to solve for the integrating factor, thanks!
To find an intgrating factor arrange the equation into the form
$\displaystyle \displaystyle \frac{dy}{dx}+ p(x)\times y = q(x)$
Once you have done this the integrating factor is simply $\displaystyle \displaystyle e^{\int p(x) dx}$
Not in this case Pickslides. What the OP has is an equation which he/she hopes can be multiplied by a function to be turned into an EXACT differential equation. This function we are trying to find is also called an integrating factor.