$\displaystyle [x^2\exp^\frac{y}{x}-y^2]dx + xydy = 0 $

pls refer to the above equation, i need help on how to solve for the integrating factor, thanks!

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- Sep 4th 2012, 06:17 AMlawochekelintegrating factor!
$\displaystyle [x^2\exp^\frac{y}{x}-y^2]dx + xydy = 0 $

pls refer to the above equation, i need help on how to solve for the integrating factor, thanks! - Sep 4th 2012, 02:50 PMpickslidesRe: integrating factor!
To find an intgrating factor arrange the equation into the form

$\displaystyle \displaystyle \frac{dy}{dx}+ p(x)\times y = q(x)$

Once you have done this the integrating factor is simply $\displaystyle \displaystyle e^{\int p(x) dx}$ - Sep 4th 2012, 06:37 PMProve ItRe: integrating factor!
Not in this case Pickslides. What the OP has is an equation which he/she hopes can be multiplied by a function to be turned into an EXACT differential equation. This function we are trying to find is also called an integrating factor.

- Sep 5th 2012, 02:33 AMlawochekelRe: integrating factor!
thanks alot "prove it", the material proved very helpful.