questions is:

>> -d/dx(e^x y') + 2ye^x = (2-x)e^x

i need to simplify the equation to show that the finite difference method is given by:

>> -(2-h)yi-1 +4(1+h^2)yi -(2+h)yi+1 = 2h^2(2-xi)

I no how to apple the finite difference method so i get the difference equation to get the above but what is:

>> -d/dx(e^x y') + 2ye^x = (2-x)e^x

simplified so it is in the form containing y'' and y'?