i need to find the general solution of the differential equation. e^x(y'+y)=1/x i need to use the intgrating factor exp(integralp(x)dx). but when i use the equation i am unable to finish the question. can anyboday help?
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What was the integrating factor you used? Remember it needs to be in the form $\displaystyle \frac{dy}{dx}+P(x)y=f(x)$.
Last edited by adkinsjr; Aug 18th 2012 at 08:39 AM.
i divide by e^x. so the equation being dy/dx+(1/e^x)y=1/xe^x. P(x)will be 1/e^x.
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