# Work done in a spring from x=3 to x=26

• August 6th 2012, 12:53 AM
leonm92
Work done in a spring from x=3 to x=26
 This question is concerned with calculating the work required to stretch a spring. A certain 'engineering' spring does not obey Hooke's law. Instead, the tension http://place32.placementtester.com:8...nlooffgimg.gif in the spring when it is extended a distance http://place32.placementtester.com:8...gppfghemgb.gif beyond its natural length is given by http://place32.placementtester.com:8...balhhfmhje.gif Find the work done in stretching the spring from x = 3 to x = 26

What are the steps to solving this?
• August 6th 2012, 05:16 AM
emakarov
Re: Work done in a spring from x=3 to x=26
By definition, work is $\int_3^{26}T(x)\,dx$.